-20x^2=-22x+6

Solution for -20x^2=-22x+6 equation:

-20x^2=-22x+6

We move all terms to the left:

-20x^2-(-22x+6)=0

We get rid of parentheses

-20x^2+22x-6=0

a = -20; b = 22; c = -6;
Δ = b2-4ac
Δ = 222-4·(-20)·(-6)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2}{2*-20}=\frac{-24}{-40}
=3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2}{2*-20}=\frac{-20}{-40}
=1/2
$